Solve the initial value problem

$(4+$x$2)$y$+3$y$=0,$y$(0)=0,$y$(0)=8$

If the solution is

y$=$c$0+$c$1$x$+$c$2$x$2+$c$3$x$3+$c$4$x$4+$c$5$x$5+$c$6$x$6+$c$7$x$7+$

enter the following coefficients:

c$0=$

c$1=$

c$2=$

c$3=$

c$4=$

c$5=$

c$6=$

c$7=$