Solve the integral in two ways: sin5(3x)cos7(3x)dxa) Using Guidelines 1 from page 397 in Larsonb) Using Guidelines 2 from page 397 in LarsonGundelines for Evaluating Integrals Involving Sine and CosineIf the power of the sine is odd and positive, save one sine factor and convert the remaining factors to coxines. Then, expand and ietegrate.sin241xcos4xdx=(sin2x)4cos4xsinxdx=(1-cos2x)4cos4xsinxdxIf the power of the cosine is odd and positive, save ote cosine factor and convert the remaining factoes to sines. Then, expand and integrate.sin-1xcos21xdx=sin-2x(cos2x)4cosxdx=sin-1x(1-sin2x)4cosxdx