Solve the problem below. For your initial post in Brightspace, copy the description of your rectangle given in the box below and then enter your solution to all four parts (parts a, b, c, and d) of the problem. To copy the description of your rectangle, highlighting and using "copy" from here in Mobius and then using "paste" into Brightspace should work.

A rectangle has perimeter134 cm and its length is 1 cm more than twice its width.

Find the dimensions of a rectangle given that its perimeter is 134 cm and its length is 1 cm more than twice its width.

Set up your solution using the variables L for the length, W for the width, and P for the perimeter.

Part a: Using the definition of perimeter, write an equation forPin terms ofLandW.

Part b: Using the relationship given in the problem statement, write an equation forLin terms ofW.

Solve the equations from parts a and b.

Part c: The width is cm.

Part d: The length is cm.