Question: solve the question using c programming (picture 2, 3 and 4 is the manual calculation for the question 6.55) 6.55 A 1:60 scale model of

 solve the question using c programming (picture 2, 3 and 4

is the manual calculation for the question 6.55) 6.55 A 1:60 scale

model of a ship is used in a water tank to simulate

a ship speed of 10 m/s. What should be the model speed?

solve the question using c programming (picture 2, 3 and 4 is the manual calculation for the question 6.55)

6.55 A 1:60 scale model of a ship is used in a water tank to simulate a ship speed of 10 m/s. What should be the model speed? If a towing force of 10 N is measured on the model, what force is expected on the prototype? Neglect viscous effects. Given: Prototype (Ship) and its model For Prototype Speed, V = 10 m/sec 0 Towing Force (Fr), = ? Let 1 be Length of prototype (m) Let ? be Length of model (m) 1 P=10 Scale ratio of length, For model Speed (V.)=2 Towing Force, F = 10 N The variable used are Acceleration due to gravity in which model is 8m Acceleration due to gravity in which model is tested (m/sec) Acceleration due to gravity in which prototype is operated (m/sec) Step 2 For dynamic similarity exit between Ship and its model, the Froude number for model and Prototype should be equal. Fr, = Fr V Jg (1) The equation (1) yields recognizing that'g' (acceleration due to gravity) does not vary significantly on the surface of earth p van 1,8 01 V =V x 1 P =10 m/sec x 1 60 =1.29 m/sec V... = 1.29 m/sec Thus the velocity on the model The ratio of Towing force is found recognizing that Force (Fr) - mass x acceleration P V X T LV plx=x- T 1 =PLV2 The ratio of forces of model to prototype is given by (Fr). P_D?V?. (F), P,DV? X 291 PP D (F1), = (Fr). D Since both the model and prototype are operated in same water facilities P = Pp 10 Frp = 10 Nx(1) 1.29 =10 NX 60X 3600 = 2160000 N = 2160 KN Thus the towing Force acting on the Prototype is (Fr), =2160 KN *(60)

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