Question: Solve the recurrence f(n) = 2 f(n/2) + log n, f(1) = 1, exactly n is a power of 2. Derive a lower bound to

Solve the recurrence f(n) = 2 f(n/2) + log n, f(1) = 1, exactly n is a power of 2.

Derive a lower bound to search for all recurrences of a given number in a list of n numbers by comparisons.

Please show me all the work please

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