Question: Solve using lagrange multiplier M a x i m i z e f ( x , y ) = x y subject to x +

Solve using lagrange multiplier

Maximizef(x,y)=xy

subject to

x+y=1

x0

y0

After solving, if the right hand side of the equality contraint becomes 0.71, what would be the resulting change in the optimal value of f?

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