solve using matlab.

The distance d from a point P (x_p, y_p, z_p) to the line that passes through the two points A (x_A, y_A, z_A) and B (x_B, y_B, z_B) can be calculated by d = 2S/r where r is the distance between the points A and B, given by r = Squareroot (x_B - x_A)^2 + (y_B - y_A)^2 + (z_B - z_A)^2 and S is the area of the triangle defined by the three points calculated by S = Squareroot s^2_1 + s^2_2 + s^3_3 where s_1 = x_P y_A + x_A y_B + x_B y_P - (y_P x_A + y_A x_B + y_B x_p) s_2 = y_p z_A + y_A z_B + y_B z_P - (z_P y_A + z_A y_B + z_B y_P) s_3 = x_P z_A + x_A z_B + x_B z_P - (z_P x_A + z_A x_B + z_B x_P). Determine the distance of point P(2, 6, -1) from the line that passes through point A(-2, -1.5, -3) and point B(-2.5, 6, 4). First define the variables x_P, y_P, z_P, x_A, y_A, z_A, x_B, y_B, and z_B, and then use the variable to calculate s_1, s_2, s_3, and r. Finally calculate S and d