Solve $y^{\text{'}}=4x\frac{y^2}{(2^2+x^2{)}^{\frac{1}{2}}}$ subject $y(0)=-\frac{1}{42}$

At $x_1=0\mathrm{.}3,$ find $y(x_1).$

In your calculations, ensure that each step includes at least three decimal places of precision.

Use $=3\mathrm{.}14159$ and $e=2\mathrm{.}71824$