Solving for (Q^*): The next step is to solve this equation for (Q^), the quantity that maximizes profit. To do this, you need to isolate (Q^) on one side of the equation. First, combine the (Q^) terms: [ -\frac{Q^}{10} - \frac{Q^}{25} = 5 - 20 ] This simplifies to: [ -\frac{5Q^}{50} - \frac{2Q^}{50} = -15 ] And further simplifies to: [ -\frac{7Q^}{50} = -15 ] Finally, solve for (Q^) by multiplying both sides by (-50/7) to get: [ Q^ = \frac{-15 \times 50}{-7} \approx 107 \text{ units} ] So, the quantity that maximizes profit is approximately 107 units. not understand where you get the 50s