Some atomic masses

ParticleSymbolMass $($uu$)$Electronee$0\mathrm{.}00055$Protonpp$1\mathrm{.}00728$Neutronnn$1\mathrm{.}00866$Hydrogen$1$H$1$H$1\mathrm{.}00783$Helium$4$He$4$He$4\mathrm{.}00260$

Part A

Part complete

Calculate the mass defect of the nitrogen nucleus $147$N$714$N$.$ The mass MNMN of neutral $147$N$714$N is equal to $14\mathrm{.}003074$ atomic mass units.

Express your answer in atomic mass units to four significant figures.

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$0\mathrm{.}1124$

uu

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Correct

Part B

Part complete

Calculate the binding energy EBEB of the nitrogen nucleus $147$N$714$N$.$

Express your answer in megaelectron volts to four significant figures.

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EBEB $=$

$104\mathrm{.}7$

MeVMeV

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Correct

Part C

Part complete

Calculate the binding energy per nucleon of the nitrogen nucleus $147$N$714$N$.$

Express your answer in megaelectron volts to three significant figures.

$7\mathrm{.}48$

MeV$/$nucleonMeV$/$nucleon

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Correct

Part D

Calculate the mass defect of the helium nucleus $42$He$24$He$.$ The mass of neutral $42$He$24$He is given by MHe$=4\mathrm{.}002603$uMHe$=4\mathrm{.}002603$u$.$

Express your answer in atomic mass units to three significant figures.

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Hint $1$for Part D$.$ Definition of mass defect

The total mass of the individual nucleons that make up an atom is always greater than the total mass of the atom itself by an amount called the mass defect. The mass defect is equal to the binding energy $($in units of atomic mass uu$),$ which is the amount of energy required to separate the nucleus into its constituent parts.

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$\mathrm{.}0293$

uu

Review your calculations and make sure you round to $3$ significant figures in the last step.

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Part E

Calculate the binding energy EBEB of the helium nucleus $42$He$24$He$.$

Express your answer in megaelectron volts to three significant figures.

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EBEB $=$

$27\mathrm{.}2$

MeVMeV

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Review your calculations and make sure you round to $3$ significant figures in the last step.

Part F

Calculate the binding energy per nucleon of the helium nucleus $42$He$24$He$.$

Express your answer in megaelectron volts to two significant figures.

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$6\mathrm{.}8$

MeVMeV

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Incorrect; Try Again; $9$ attempts remaining

Review your calculations and make sure you round to $1$ decimal places in the last step.