SPH3U SOLVING PARALLEL AND SERIES CIRCUITS Date: Instructions: Using the approach developed in class, solve each circuit below. Remember to include your reasoning when you are solving. 2 2 W N - 10 120 3 2. R P 90 1 2 3 30 N - W N - 10 3 2 V R P NV 10 3 N - W N - 40 6 V 1 R P 4 10 2 3 A W N J WA 30 90 OT V 1 R P 3 20 80 400 U A W N - 2 -4 5 60 T 240 30Mon 10/1 JUNCTION RULE tattoos to dat part wo o i Current in = current out pas tis tonew 's at of LOOP RULE : Voltage gains Voltage drops = 0 OHM'S LAW V = IR R = V I I = V R WATT'S LAW mp = IV 810 P = IZR R = VER # 5 go0 V V= IR R P 160 8 20 P - IV 1280 IV W N S 80 5 V = IR 16 400 20 3 6 . 7 60 4 60 I 60 60 60 V = IR 2A P = I2R 30 120 240 8 30 19 20 PARALLEL Same Vollage Split Current SERIES Same Current Split Voltage Battery DC Source T AC Source load or Resistor