Question: Stack S1 Stack S2 Enqueue(x) S1.push(x) Dequeue(x) if (S1 is empty) while(S1 is not empty) S2.push(S1.pop()) S2.pop() What is the amortized cost of dequeue? Select

Stack S1 Stack S2 Enqueue(x) S1.push(x) Dequeue(x) if (S1 is empty) while(S1 is not empty) S2.push(S1.pop()) S2.pop() What is the amortized cost of dequeue? Select one: a. On?) ob. O(n log n) c. O(log n) o d. O(n) e. O(1)

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