Question: Stack S1 Stack S2 Enqueue(x) S1.push(x) Dequeue(x) if (S1 is empty) while(S1 is not empty) S2.push(S1.pop()) S2.pop() What is the amortized cost of enqueue? Select

Stack S1 Stack S2 Enqueue(x) S1.push(x) Dequeue(x) if (S1 is empty) while(S1 is not empty) S2.push(S1.pop()) S2.pop() What is the amortized cost of enqueue? Select one: a. O(n) b. O(n log n) O c. O(1) d. O(log n) e. O(n)

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