standard condition $($P $=1\mathrm{.}0$ atm, T $=0\mathrm{.}0$oC$),$ a $1\mathrm{.}0-$meter$-$long, $1\mathrm{.}6-$cm$-$diameter glass tube open at both ends is dipped into a $60\mathrm{.}0-$cm$-$deep mercury container, with the upper end in air and the lower end to the bottom of the container. The tube is tilted by $45$o and the mercury level inside the tube is aligned with that outside the tube $($neglecting the capillarity$).$ Now you seal the upper opening completely and slowly push the tilted tube back to upright. $($a$)$ How high would be the mercury level inside the tube relative to that in the container? What is the pressure $($in atm$)$ of the sealed air in the tube?