Question: start -> s start S s -> aS S aS S aB aS aaB B bS aaB aabS S aB aabS aabaB B b aabaB
| start -> s | start | S |
| s -> aS | S | aS |
| S aB | aS | aaB |
| B bS | aaB | aabS |
| S aB | aabS | aabaB |
| B b | aabaB | aabab |
draw a parse tree for this derivation
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