Question: Starting from an initial interval (2, 3) containing 5, we will simply take the midpoint of the interval and determine whether 5 is contained

Starting from an initial interval (2, 3) containing 5, we will simply take the midpoint of the interval and determine whether 5 is contained in which of the two subintervals divided by the midpoint, i.e., whether 5 is greater or less than the midpoint . For instance, let's call b = 2 be the first approximation and b = 2.5 be the second approximation determined by the midpoint of 2 and 3. Since 2

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Using the method described we have b 2 b 232 25 Since 2 5 25 we take the midpoint of 2 25 as the nex... View full answer

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