{

static final int BONUS_POINTS = 5;

static void addBonus(int[] array1, int[] shouldAdd)

{

for (int i = 0; i < array1.length; i++)

{

if (shouldAdd[i] == 1)

{

array1[i] = array1[i] + BONUS_POINTS;

}

}

}

static double calculateStat1 (int[] a)

{

int s = 0;

for (int i = 0; i < a.length; i++)

{

s = s + a[i];

}

return s / (double)a.length;

}

static double calculateStat2(int[] a, double s1)

{

double s = 0;

for (int i = 0; i < a.length; i++)

{

s = s + (a[i] - s1) * (a[i] - s1);

}

return (Math.sqrt(s) / (a.length - 1));

}

public static void main(String[] args)

{

int data[] = { 42, 97, 64, 53, 78, 96, 83 };

int bonus[] = { 0, 1, 1, 0, 0, 1, 1 };

addBonus(data, bonus);

double stat1 = calculateStat1(data);

System.out.println("The first static is " + stat1);

double stat2 = calculateStat2(data, stat1);

System.out.println("The second statistic is " + stat2);

for (int i = 0; i < data.length; i++)

{

System.out.print(data[i] + " is ");

double distance = (data[i] - stat1) / stat2;

System.out.print(distance + " from " + stat1 + " which is a");

if (distance < -1.5)

{

System.out.println("n F");

}

if ((distance >= -1.5) && (distance < -0.5))

{

System.out.println(" D");

}

if ((distance >= -0.5) && (distance < 0.5))

{

System.out.println(" C");

}

if ((distance >= 0.5) && (distance < 1.5))

{

System.out.println(" B");

}

if (distance >= 1.5)

{

System.out.println("n A");

}

}

}

}

QUESTION:

Use the above code to answer the question:

In caclculateStat1(), how would the behiavior be different if the length of the array was not typecast to double?

Please be as detailed as possible. Thank you!