Question: - Steam is generated at high pressure around 150 bar and temperature 538C. - D= The desalted output =757.7kg/s. - 77.22kg of steam is diverted

 - Steam is generated at high pressure around 150 bar and

temperature 538C. - D= The desalted output =757.7kg/s. - 77.22kg of steam

- Steam is generated at high pressure around 150 bar and temperature 538C. - D= The desalted output =757.7kg/s. - 77.22kg of steam is diverted to MSF (between IP and LP). - This work is considered as turbine work loss due to steam extraction, and its heat equivalent is the heat supply to the MSF units. - Mass flow rate to LP turbine: 133kg/s - Power output is 74.66MW 1. What is the specific power of the LP turbine? 2. What is the lost work due to the extraction of steam before the LP? - The steam has the same enthalpy at the inlets to the LP turbine and desalters ,h8=2,961kJ/kg, Leaves the desalters as condensate at 100C,hf=419kJ/kg 3. What is the heat supplied to the desalter? - Steam with a flow rate of 77.22kg/s with an energy content of xxxMW is used for desalination. - It could have been used by the LP turbine to produce work of 43.432MW. - By being introduced into the MSF units instead, the associated specific (per unit produced water) equivalent work is 57.06kJ/(kg desalted water). (43.432 MW/ 757.7kg/s.) 4. What is the specific (per unit produced water) equivalent work in KWh/m3 ? 5. What is the specific fuel energy input (Qf/D) -asssuming that npp=0.36 ? - Assuming specific energy for pumping: 14.4kJ/kg(4kWh/m3) 6. What is then the total specific work in kJ/(kg desalted water)? 7. What is the total specific fuel energy input (Qf/D) -assuming.that npg=0.36 ? Answer in kj/kg (same as Mj/m3, considering the density of water) 8. What is the rate of Energy 9. What is the Rate of fuel energy required to deliver the required desalting capacity? (D) - Steam is generated at high pressure around 150 bar and temperature 538C. - D= The desalted output =757.7kg/s. - 77.22kg of steam is diverted to MSF (between IP and LP). - This work is considered as turbine work loss due to steam extraction, and its heat equivalent is the heat supply to the MSF units. - Mass flow rate to LP turbine: 133kg/s - Power output is 74.66MW 1. What is the specific power of the LP turbine? 2. What is the lost work due to the extraction of steam before the LP? - The steam has the same enthalpy at the inlets to the LP turbine and desalters ,h8=2,961kJ/kg, Leaves the desalters as condensate at 100C,hf=419kJ/kg 3. What is the heat supplied to the desalter? - Steam with a flow rate of 77.22kg/s with an energy content of xxxMW is used for desalination. - It could have been used by the LP turbine to produce work of 43.432MW. - By being introduced into the MSF units instead, the associated specific (per unit produced water) equivalent work is 57.06kJ/(kg desalted water). (43.432 MW/ 757.7kg/s.) 4. What is the specific (per unit produced water) equivalent work in KWh/m3 ? 5. What is the specific fuel energy input (Qf/D) -asssuming that npp=0.36 ? - Assuming specific energy for pumping: 14.4kJ/kg(4kWh/m3) 6. What is then the total specific work in kJ/(kg desalted water)? 7. What is the total specific fuel energy input (Qf/D) -assuming.that npg=0.36 ? Answer in kj/kg (same as Mj/m3, considering the density of water) 8. What is the rate of Energy 9. What is the Rate of fuel energy required to deliver the required desalting capacity? (D)

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