Step $2$

$We$ now need $to$ determine $if\underset{xa}{lim}f(x)$ exists. $We$ check this using direct substitution.

$\underset{x4}{lim}x\sqrt[\phantom{2}]{41-x^2}=(,)\sqrt[\phantom{2}]{41-4^2}$

$=$

$We$ can conclude that $\underset{xa}{lim}f(x)$