Question: Step 6We can move all the I terms to one side and get25/9I=13e3sin(4)-49e3cos(4)C1Step 7And now we finally havee3sin(4)d=I=9e3sin(4)75-4e3cos(4)25C, where C=925C1Putting all of this together and

Step 6We can move all the I terms to one side and get25/9I=13e3sin(4)-49e3cos(4)C1Step 7And now we finally havee3sin(4)d=I=9e3sin(4)75-4e3cos(4)25C, where C=925C1Putting all of this together and incorporating the constant of integration, C, we havee3sin(4)d=

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