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For an ideal battery $(r=0),$ closing the switch in $($Figure $1)$ does not affect the brightness of bulb A$.$ In practice, bulb A dims just a little when the switch closes. To see why, assume that the $1\mathrm{.}50$ V battery has an internal resistance $r=0\mathrm{.}70$ and that the resistance of a glowing bulb is $R=6\mathrm{.}00.$

Figure

$1$ of $1$

Part C

By what percent does the current through A change when the switch is closed?

Express your answer as a percentage.

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