Question: Substituting this back into the function, we have lim h 0 ( 2 + h ) 3 8 h = lim h 0 ( 8

Substituting this back into the function, we have
limh0
(2+ h)38h
=limh0
(8+12h +6h2+ h3)8h
=limh0
h + h2+ h3h
.

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