Question: Substitution method Determine with which value the equation has two real roots. 4*-(a+1)2*+a=0 9*-(a+1)3*+a=0 22x-(a+1)2*+a=0 32x-(a+1)3*+a=0 t2= 22x t2 = 32x t=2x t=3x 12-(a+1)t+a=0 tz-(a+1)t+a=0

Substitution method Determine with which value
Substitution method Determine with which value the equation has two real roots. 4*-(a+1)2*+a=0 9*-(a+1)3*+a=0 22x-(a+1)2*+a=0 32x-(a+1)3*+a=0 t2= 22x t2 = 32x t=2x t=3x 12-(a+1)t+a=0 tz-(a+1)t+a=0 D=b2-4ac=(a+1)2-4.1.a=? D=b2-4ac=(a+1)2-4.1.a=? t= b + VD =? -b+ VD =? 2a t= 2a t,= - b- VD =? to= - b- VD =? 2 a 2 a

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