Subtract ${131}_{\text{D}\text{E}\text{C}\text{I}\text{M}\text{A}\text{L}}$ from ${11}_{\text{D}\text{E}\text{C}\text{I}\text{M}\text{A}\text{L}}$ using $9-$bit two's complement arithmetic $($i$.$e$.11-131)$:

Convert each decimal number to binary, perform negation on the subtrahend, and

then use addition. $($i$.$e$.$ instead of $11-131$ perform $11+(-131),$ in $9$ bit $2\text{'}$s complement

signed system.$)$

Check your answer using base$-10$ math.

Did $9-$bit two's complement overflow occur?

Be very careful with this problem!

$(4$ points$)$