Suppose ${\displaystyle \underset{0}{\overset{5}{}}}f(x)dx=3,{\displaystyle \underset{5}{\overset{8}{}}}f(x)dx=-5,$ and ${\displaystyle \underset{5}{\overset{8}{}}}g(x)dx=7.$ Evaluate the integrals in parts $a-d.$

a$.{\displaystyle \underset{0}{\overset{5}{}}}4f(x)dx=($Simplity your answer$)$

b$.{\displaystyle \underset{5}{\overset{a}{}}}-6g(x)dx=($Simplity your answer$)$

c$.{\displaystyle \underset{5}{\overset{}{}}}[9f(x)-g(x)]dx=($Simplify your answer$)$

d$.{\displaystyle \underset{8}{\overset{5}{}}}[f(x)+6g(x)]dx=($simplify your answer.$)$