Question: Suppose a 500. mL flask is filled with 0.40 mol of NO2 and 1.1 mol of NO. The following reaction becomes possible: NO3(g) + NO(g)

Suppose a 500. mL flask is filled with 0.40 mol of

Suppose a 500. mL flask is filled with 0.40 mol of NO2 and 1.1 mol of NO. The following reaction becomes possible: NO3(g) + NO(g) = 2NO2(g) The equilibrium constant K for this reaction is 2.66 at the temperature of the flask. Calculate the equilibrium molarity of NO3. Round your answer to two decimal places. IM

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