Suppose f: [0, 13] R is a piecewise-defined function -16x+60+9, 1/2 pr+qx+r, (a) Give a short proof why if 121 p + 11q+r = 14, then fis continuous at x = 11. Q Equation Editor f(x) = - if 0x 11 if 11 < x < 13. A- A-T BIUS X, x Styles Font Size Words: 0 (b) Suppose you are given some real number r. Select the correct statement below. There is no p and q such that f is differentiable at x = 11. There is a unique p and q such that f is differentiable at x = 11. There are infinitely many p and q such that f is differentiable at x = 11. Suppose r = -4. Find some values of p and q that work. If there is no such p and q. enter the word none. P, q= Syntax advice for (b) and (c): Enter your values in the correct order, exact values (no approximation), and separated by a comma. For example if your answer is p = 1/8 and q = 4 then just enter 1/8, 4 (do not enter 4, 1/8) (c) Assume you are still given the real number r = -4 as above. Select the correct statement below. There is no p and q such that f is differentiable everywhere in [0, 13].