Question: Suppose f is a differentiable function with f(7) =1 and f'(7) =-1. Let y=f(x) . tanxte . cosx. Then the value of y at x

 Suppose f is a differentiable function with f(7) =1 and f'(7)=-1. Let y=f(x) . tanxte . cosx. Then the value of yat x =1 is... Olten O-1ten 01-eT 0 -1-em O eTAt whatpoints on the curve y: col: :1: is the tangent line parallel

to the line 3;: a: ? Choose the correct xvaluels) below. \fLetf(x) = sin x , g(x) =et and h(x) =25 . Ifs=hofog, what is s'(x) ? O 5ez sin* (ex) cos(ex) O 5esin(a) cos x O 5ac cos(x) ex O 5etz sin (ex) cos(ex)

Suppose f is a differentiable function with f(7) =1 and f'(7) =-1. Let y=f(x) . tanxte . cosx. Then the value of y at x =1 is... Olten O-1ten 01-eT 0 -1-em O eTAt what points on the curve y: col: :1: is the tangent line parallel to the line 3;: a: ? Choose the correct xvaluels) below. \fLet f(x) = sin x , g(x) =et and h(x) =25 . If s=hofog, what is s'(x) ? O 5ez sin* (ex) cos(ex) O 5e sin(a) cos x O 5ac cos(x) ex O 5etz sin (ex) cos(ex)

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