Question: Suppose f is three time differentiable function on - 1 , 1 such that f ( - 1 ) = 0 , f ( 1

Suppose f is three time differentiable function on -1,1 such that f(-1)=0,f(1)=1 and f'(0)=0. Now using Taylor theorem prove that f'''(c)3 for some cin(-1,1). Hint: Divide the interval into two parts -1,0 and 0,1 and use Taylor's thorem to obtain f(c1)+f(c2)=6, where c1in(-1,0) and c2in(0,1). This implies one of these values greater than or equal to 3
Suppose f is three time differentiable function

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