Suppose that $f$ is a function given as $f(x)=x^2-4x-3.$

Simplify the expression $f(x+h).$

$f(x+h)=$

$$

Simplify the difference quotient, $\frac{f(z+h)-f(z)}{h},$

$\frac{f(z+h)-f(x)}{h}=$

$$

The derivative of the function at $x$ is the limit of the difference quotient as $h$ approaches zero.

$f^{\text{'}}(x)=\underset{h0}{lim}\frac{f(x+h)-f(x)}{h}=$

$$