Suppose that $f$ is an odd continuous function defined for all real numbers. Which of the following statements is true about the integral

${\displaystyle \underset{-1}{\overset{1}{}}}\frac{f(x)}{1x^2}dx$

Choose the correct answer.

The integral equals twice the area under the curve between $x=0$ and $x=1.$

The value of the integral is nero.

We cannot use the fundamental theorem of calculus to evaluate the integral because the integrand does not have an antiderivative.

The integral does not evist because the integrand is not continuous.

It is impossible to determine the value of the integral.