Suppose that your first guess with Newton's method is lucky, in the sense that x0 is a root of f(x) = 0. Assuming that f' (x0) is defined and not 0, what happens to x1 and later approximations? Choose the correct answer below. [:1 A. x1 and later approximations will move to other solutions of the equation f(x) = 0. Cl B. x1 and later approximations will move away from the root. 0 C. x1 and later approximations will all be equal to x0. C) D. x1 and later approximations will all be equal to D