Suppose the ball is thrown from the same height as in the PRACTICE IT problem at an angle of 33.0 below the horizontal. If it strikes the ground 39.5 m away, find the following. (Hint: For part (a), use the equation for the x-displacement to eliminate v0t from the equation for the y-displacement.) (a) the time of flight 1.51 Incorrect: Your answer is incorrect. The x coordinate as a function of time is x(t) = cos(33.0)t, so the initial speed is v0 = x/(cos 33.0t), where x = 39.5 and t is the time of flight. Insert this into your equation for y(t) and solve for the time of flight. Note that the answer should be smaller than 2.893, since the ball is thrown down (and to the right). s (b) the initial speed 35.6 Incorrect: Your answer is incorrect. Make sure you have a fixed coordinate system. For instance, is the origin (0, 0) at the base of the building? If so, then the initial height of the ball is 41.0 m. Is the origin instead at the initial position of the ball? If so, then the ball lands when its y-coordinate is equal to 41.0 m. m/s (c)