Suppose the ball is thrown from the same height as in the PRACTICE IT problem at an angle of 33.0 below the horizontal. If it strikes the ground 45.3 m away, find the following. (Hint: For part (a), use the equation for the x-displacement to eliminate vz from the equation for the y-displacement.) (a) the time of flight i x The x coordinate as a function of time is x{#) = cos(33.0), so the initial speed is Vg = Ax/(cos 33.0Af), where Ax = 45.3 and Az is the time of flight. Insert this into your equation for y(z) and solve for the time of flight. Note that the answer should be smaller than 3.162, since the ball is thrown down {and to the right). s (b) the initial speed (c) the speed and angle of the velocity vector with respect to the horizontal at impact speed [ Jmis angle [ | below the horizontal