Question: Suppose the charity advertising budget problem with a maximization objective function in Lecture 9 has a value of 3 . 2 as the Lagrange multiplier

Suppose the charity advertising budget problem with a maximization objective function in Lecture 9 has a value of 3.2 as the Lagrange multiplier of the budget constraint (x1+ x2<=400,000) in the optimal solution. What is the correct interpretation? Group of answer choices When the constraint becomes x1+ x2<=400,001 or 399,999, the objective value will increase or decrease, respectively, by 3.2. When the constraint becomes x1+ x2<=399,999, the objective value will increase by 3.2. When the constraint becomes x1+ x2<=400,000\pm 3.2, the objective value will remain unchanged. When the constraint becomes x1+ x2<=400,001, the objective value will decrease by 3.2.

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