Suppose the following code is given(division () is integer division) int update(int *p) { *p=*p+2; return...

 

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Suppose the following code is given(division () is integer division) int update(int *p) { *p=*p+2; return (*p)+2 } void main() { int i-20.j-20, sum1,sum2; sum1=(1/2)+update(&i); sum2=update(&i)+(j/2); } What are the values of sum1 and sum2? a- If the operands in the expressions are evaluated left to right? b- If the operands in the expressions are evaluated right to left? c- Are sum1 and sum2 same? Why? Suppose the following code is given(division () is integer division) int update(int *p) { *p=*p+2; return (*p)+2 } void main() { int i-20.j-20, sum1,sum2; sum1=(1/2)+update(&i); sum2=update(&i)+(j/2); } What are the values of sum1 and sum2? a- If the operands in the expressions are evaluated left to right? b- If the operands in the expressions are evaluated right to left? c- Are sum1 and sum2 same? Why?

Answer rating: 100% (QA)

a If the operands in the expressions are evaluated left to right For sum1 1 12 evaluates to 12 2 upd... View the full answer