Suppose the virtual address space is $1$Mbytes, the physical memory size is $4$Mbytes, and the page$/$frame size is $16$ Kbytes. So we will have:

i$.$ Number of bits for virtual$/$logical address $=,t=20$ bits

ii$.$ Number of bits for physical address $=q,PA=22$ bits

iii. Number of bits for offset $($d$)=q,d=14$ bits

iv$.$ Number of bits for page number $(p)=p=6$ bits

v$.$ Number of bits for frame number $(f)=q,f=8$ bits

Suppose you are writing a C program to translate a given logical$/$virtual address $($LA$)$ to a physical address $($PA$)$ in the above system. Using the given bits above, show us what $C$ statements would you use to determine pnum, fnum, and PA$.$

unsigned int pnum, dnum, fnum $,PA$;

unsigned int LA$=0$xF$28$A$3$; $//11110010100010100011$

dnum $=$

$//$ give your statement using the following format with the correct flag and put just one space character between tokens