Question: Suppose we modify the deterministic version of the quick-sort algorithm so that, instead of selecting the last element in an n-element sequence as the pivot,

Suppose we modify the deterministic version of the quick-sort algorithm so that, instead of selecting the last element in an n-element sequence as the pivot, we choose the element at index n/2, that is, an element in the middle of the sequence. What is the running time of this version of quick-sort on a sequence that is already sorted?

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