Suppose we write the following code (pseudo-code) on our shell terminal: int main(int argc, char *argv[])...

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Suppose we write the following code (pseudo-code) on our shell terminal: int main(int argc, char *argv[]) { int p fork(); for (int i=0; i<=p; i++) { waitpid(p); printf ("P_id_1: %d, P_id_2: %d, i = %d\n", getpid(), p, i); p = fork(); } } Let's execute the code above. What do you observe and why? What is the printout? How many processes are being created? Suppose we write the following code (pseudo-code) on our shell terminal: int main(int argc, char *argv[]) { int p fork(); for (int i=0; i<=p; i++) { waitpid(p); printf ("P_id_1: %d, P_id_2: %d, i = %d\n", getpid(), p, i); p = fork(); } } Let's execute the code above. What do you observe and why? What is the printout? How many processes are being created?

Answer rating: 100% (QA)

Answer The provided code appears to be a C program that creates multiple child processe... View the full answer