t s(t) Interpretation 0 0 2 170 At two seconds of travel, the rocket is .... ft high. 4 210 At four seconds of travel, the rocket is .... Ft high appx. 10 -438 How far down the rocket could travel theoretically. 150 The equation equal time elapsed, and distance traveled up. 150 The equation is not a practical answer because of the above time and distance. 200 The ascent takes 2.66 seconds. 200 The descent takes 4.7 seconds. The initial height of rocket still on the ground with zerotime elapsed t=0. A=-16 B= 116 C=2 How long will it take the rocket to reach its greatest height? ... seconds What is the maximum height reached by the rocket? How long will it take the rocket to get to the ground? ... second appx. 116 b2 4 ac x= 2(16) 438 = 16(t) +116t +2 t= 116 b24 ac 32 t=0, -16(0) ^2 + 116(0) + 2= 0 t=2, -16(2) ^2 + 116(2) +2= 170 t =4, -16(4) ^2 + 116(4) + 2= 210 t= 10, -16(10) ^2 + 116(10) +2= -438 150= -16(t) ^2 +116(t) + 2 = 200= -16(t) ^2 + 116(t) + 2 =