$\backslash$table$[[\frac{?}{\text{b}\text{a}\text{r}}(Op-$code $),$Operand,Description$],[1,$RXY$,\backslash$table$[[$LOAD the register $R$ with the bit pattern found in the memory cell whose address is $xY.],[$Example: $14A3$ would cause the contents of the memory cell located at address $A3$ to be placed in register $4.]]],[2,$RXY$,\backslash$table$[[$LOAD the register $R$ with the bit pattern $xY.],[$Example: $20A3$ would cause the value $A3$ to be placed in register $0.]]],[3,$RXY$,\backslash$table$[[$STORE the bit pattern found in register $R$ in the memory cell whose address is XY$.],[$Example: $35B1$ would cause the contents of register $5$ to be placed in the memory cell whose address is B$1.]]],[4,$ORS,$\backslash$table$[[$MOVE the bit pattern found in register $R$ to register $S.],[$Example: $40A4$ would cause the contents of register $A$ to be copied into register $4.]]],[$B$,$RXY$,\backslash$table$[[$JUMP to the instruction located in the memory cell at address XY if the bit pattern in register $R$ is equal to the$],[$bit pattern in register number $0.$ Otherwise, continue with the normal sequence of execution. $($The jump is$],[$implemented by copying XY into the program counter during the execute phase.$)],[$Example: $B43C$ would first compare the contents of register $4$ with the contents of register $0.$ If the two were$],[$equal$,$ the pattern $3C$ would be placed in the program counter so that the next instruction executed would be$],[$the one located at that memory address. Otherwise, nothing would be done and program execution would$],[$continue in its normal sequence.$]]],[$c$,000,\backslash$table$[[$HALT execution.$],[$Example: CO$00$ would cause program execution to stop.$]]]]$

When answering the following questions, assume that the machine starts with its program counter equal to $20.$

$\backslash$table$[[$Address$,$Content$],[20,12],[21,23],[22,32],[23,30],[24,C0$