Question: TABLE B (continued) P n X 0.05 0.1 0.2 0.25 0.3 0.4 0.5 0.6 0.7 0.75 0.8 0.9 0.95 18 0 0.397 0.150 0.018 0.006

 TABLE B (continued) P n X 0.05 0.1 0.2 0.25 0.30.4 0.5 0.6 0.7 0.75 0.8 0.9 0.95 18 0 0.397 0.150

TABLE B (continued) P n X 0.05 0.1 0.2 0.25 0.3 0.4 0.5 0.6 0.7 0.75 0.8 0.9 0.95 18 0 0.397 0.150 0.018 0.006 0.002 1 0.376 0.300 0.081 0.034 0.013 0.001 2 0.168 0.284 0.172 0.096 0.046 0.007 0.001 3 0.047 0.168 0.230 0.170 0.105 0.025 0.003 4 0.009 0.070 0.215 0.213 0.168 0.061 0.012 0.001 0.001 0.022 0.151 0.199 0.202 0.115 0.033 0.004 0.005 0.082 0.144 0.187 0.166 0.071 0.015 0.001 0.001 0.035 0.082 0.138 0.189 0.121 0.037 0.005 0.001 0.012 0.038 0.081 0.173 0. 167 0.077 0.015 0.004 0.001 0.003 0.014 0.039 0.128 0.185 0.128 0.039 0.014 0.003 0.001 0.004 0.015 0.077 0.167 0.173 0.081 0.038 0.012 0.001 0.005 0.037 0.121 0.189 0.138 0.082 0.035 0.001 0.001 0.015 0.071 0.166 0.187 0.144 0.082 0.005 0.004 0.033 0.115 0.202 0.199 0.151 0.022 0.001 0.001 0.012 0.061 0.168 0.213 0.215 0.070 0.009 15 0.003 0.025 0.105 0.170 0.230 0.168 0.047 16 0.001 0.007 0.046 0.096 0.172 0.284 0.168 17 0.001 0.013 0.034 0.081 0.300 0.376 18 0.002 0.006 0.018 0.150 0.397If X is a binomial random variable with N = 18, and P = 0.1, then P(X = 2) = 0.168. O True O False

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