Question: Task 2 : Loads on casing W now turn to the problem of calculating loads on a casing string, and consider a vertical well with
Task : Loads on casing
W now turn to the problem of calculating loads on a casing string, and consider a vertical well with the current section drilled to using a mud with density A in production casing will be run to the bottom of the section. The formation pressure at the bottom of the section at a depth of is estimated to be bar. After running and cementing the casing, we plan to drill the next section with a mud of density
It is estimated that the loss of mud to a possible lowpressure zone will empty maximum of the casing. The required safety factors are for tearoff, against bursting, and against collapse. Density of any gas in annulus is assumed to be When mud is still for a long period of time it can degenerate into a density of the weight material falls out of the mud, but not the salt
a Find the maximum burst pressure in a possible gas kick situation. At which depth is the strain bursting pressure on the casing maximum? Explain your answer.
b Find the maximum collapse pressure in case of mud losses to the lowpressure zone. At which depth is the strain on the casing maximum? Explain your answer.
When cementing the in production casing, a cement slurry with a density of is to be used. The fluid used to pumppush the cement down the casing has a density which is the mud to be used for further drilling The top of the cement should be at above the bottom casing shoe of the previous casing, which goes down to a depth of We assume a "worst case" scenario, with the cement slurry completely filling the casing during injection. The critical fracture pressure for the cementing operation is at a depth of If this pressure is exceeded, we need to repair it by a second stage cementing operation.
c Calculate the maximum burst pressure and maximum collapse pressure when cementing. At which depth is the strain on the casing maximum? Do we have to repair and perform a second stage cementing operation? Explain your answers!M
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