Question: te Y ( 1 . 5 ) where Y ( x ) is a solution of the initial - value problem ' = 3 x

te Y(1.5) where Y(x) is a solution of the initial-value problem '=3xF2(1)=16.(found rour answer to two decimal places.)
te Y ( 1 . 5 ) where Y ( x ) is a solution of the

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