Test $2$ Problem $3$ Trusses, Method of Joints: The test problem was The ideal truss is shown, Supports A and $\backslash ($ K $\backslash )$ are both anchored frictionless pins. Vertical downword forces are opplied of pins $\backslash ($ C $\backslash )$ and $\backslash ($ E $\backslash ).$ The support reoctions are $\backslash ($ A x$=67501\backslash$mathrm$\{$bf$\}\backslash )$ to right, $\backslash (\backslash$mathrm$\{$Ag$\}=300010\backslash$mathrm$\{$f$\}\backslash )$ up$,\backslash ($ K x$=675010\backslash$mathrm$\{$f$\}\backslash )$ to left, and $\backslash ($ K y$=0\backslash ).$ The truss is stable and statically determinate.

a$.$ Why is $\backslash ($ K y$=0\backslash )?$

b$.$ Identify oll obvious zero force members $($ZFM$),$ stoting which criterio applied to those identified os such, if any. Mork each ZFM with a circle drown on the member in the picture.

c$.$ Using the method of Joints only, find the forces in truss members $\backslash ($ A$,$ A B $\backslash ),$ and Kl $,$ indicating whether each is in tension or compression. Test $2$ Problem $3$ Trusses, Method of Joints: The test problem was The ideal truss is shown, Supports A and $\backslash ($ K $\backslash )$ are both anchored frictionless pins. Vertical downword forces are opplied of pins $\backslash ($ C $\backslash )$ and $\backslash ($ E $\backslash ).$ The support reoctions are $\backslash ($ A x$=67501\backslash$mathrm$\{$bf$\}\backslash )$ to right, $\backslash (\backslash$mathrm$\{$Ag$\}=300010\backslash$mathrm$\{$f$\}\backslash )$ up$,\backslash ($ K x$=675010\backslash$mathrm$\{$f$\}\backslash )$ to left, and $\backslash ($ K y$=0\backslash ).$ The truss is stable and statically determinate.

a$.$ Why is $\backslash ($ K y$=0\backslash )?$

b$.$ Identify oll obvious zero force members $($ZFM$),$ stoting which criterio applied to those identified os such, if any. Mork each ZFM with a circle drown on the member in the picture.

c$.$ Using the method of Joints only, find the forces in truss members $\backslash ($ A$,$ A B $\backslash ),$ and Kl $,$ indicating whether each is in tension or compression.