thank you! The curve below has a horizontal tangent line at the point ( 4, 1)
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The curve below has a horizontal tangent line at the point ( – 4, 1) and at one other point. Find the coordinates of the second point where the curve has a horizontal tangent line. 9x² + 72x + 25y² + 200y = - 319 x-coordinate of second point = y-coordinate of second point = Preview Preview - Find an equation of the tangent line to the graph of x³ + 3xy² + y = 15 at the point (1, 2). y= Preview The curve below has a horizontal tangent line at the point ( – 4, 1) and at one other point. Find the coordinates of the second point where the curve has a horizontal tangent line. 9x² + 72x + 25y² + 200y = - 319 x-coordinate of second point = y-coordinate of second point = Preview Preview - Find an equation of the tangent line to the graph of x³ + 3xy² + y = 15 at the point (1, 2). y= Preview
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SOLUTION given that 2 9 x 7 2 x 2 5 Y 200y 319 P 41 differentiate with respect to x 18 x 7 ... View the full answer
Related Book For
College Mathematics for Business Economics Life Sciences and Social Sciences
ISBN: 978-0321614001
12th edition
Authors: Raymond A. Barnett, Michael R. Ziegler, Karl E. Byleen
Posted Date:
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