The $10\%$ NaOH solution is fed to the $1$st unit of a triple$-$action evaporator at a temperature of $300$ K with a flow rate of $10$ kg$/$h$.$ The pressure in the $3$rd effect is $13\mathrm{.}3$ kN$/$m$2$ and the NaOH taken from this effect is $40\%.$ The heat of heating of the solution is $4\mathrm{.}18$ kJ$/$kg$.$ K can be taken. The elevation of the boiling point will not be neglected. The steam is saturated water vapor at a pressure of $205$ kN$/$m$2$ and is fed to the $1$st effect and the condensate is separated as a saturated liquid. If the heating areas are equal, calculate the areas, temperature differences and steam consumption. $($U$1=5$ kW$/$m$2.$ K$,$ U$2=3\mathrm{.}2$ kW$/$m$2.$ K$,$ U$3=1\mathrm{.}4$ kW$/$m$2.$ K$)$