The 230,000 lb space-shuttle orbiter touches down at about 220 mi/hr. At 200 mi/hr its drag parachute deploys. At 35 mi/hr, the chute is jettisoned from the orbiter. If the deceleration in feet per second squared during the time that the chute is deployed is -0.0003v^2 (speed v in feet per second), determine the corresponding distance (in feet) traveled by the orbiter. Assume no braking from its wheel brakes.

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initial speed V 220 mihr I Velocity when chute is deployed V 20... View the full answer