The $40-kg$ body A has a speed of $4\frac{m}{s}$ at the moment shown, and force $P$ is $20$ N acting as shown.

If the coefficient of kinetic and static friction between the body A and the vertical bar is $k=0\mathrm{.}3$

and $s=0\mathrm{.}4.$

Q$2\mathrm{.}1$ a

$1$ Point

Determine the change in speed of $A.$ Solution lies in $(-14\mathrm{.}89,-5\mathrm{.}7)$