The alternative that provides Weiss the greatest expected monetary value $($EMV LOADING... $)$ is

Build New Plant

$.$

Part $5$

The value of the return under this decision is $$$$285000285000($enter your answer as a whole$$ number$).$

Part $6$

$$b$)$ The expected value of perfect information $($EVPI LOADING... $)$ for Weiss$=$$enter your response here $($enter your answer as a whole$$ number$).$